1 solutions
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0
C :
#include<stdio.h> void fun(int *pa); int main() { int a[9]; int i; for(i=0;i<9;i++) scanf("%d",&a[i]); fun(a); } void fun(int *pa) { int i,sum = 0; for(i=0;i<9;i++) sum += *(pa+i); printf("%d",sum); }
C++ :
#include<iostream> using namespace std; int main() { int i,a[9],*p,*sum; for(i=0;i<9;i++) cin>>a[i]; p=&a[0]; sum=new(int); *sum=0; for(i=0;i<9;i++) { *sum+=*p; p++; } cout<<*sum<<endl; return 0; }
- 1
Information
- ID
- 492
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By