1 solutions
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0
C :
#include<stdio.h> int len(char *p); int main () { char a[100]; int n; gets(a); n=len(&a); printf("%d\n",n); return 0; } int len(char *p) { int i,c=0; for(i=0;*(p+i) !=0;i++) c++; return c; }
C++ :
#include <bits/stdc++.h> using namespace std; int Strlen(char *str){ int i=0; while(*str++!='\0') i++; return i; } int main(){ char a[100]; gets(a); cout<<Strlen(a); return 0; }
- 1
Information
- ID
- 496
- Time
- 1000ms
- Memory
- 12MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By