1 solutions
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0
C :
#include<stdio.h> main() { int j; long long k=0;; long long i; int m; long long sum=0; long long n; int a[100000]={0}; scanf("%lld",&n); for(i=1;i<=n;i++) { sum+=i; //k++; // printf("%d",sum); } printf("%lld",sum); }
C++ :
#include <iostream> using namespace std; long long n,f,j; int main() { cin>>n;j=0; for (f=1;f<=n;f++) { j+=f; } cout<<j; return 0; }
Pascal :
var n,i:longint; k:int64; begin readln(n); for i:=1 to n do k:=k+i; writeln(k); end.
Python :
# coding=utf-8 a=1 s=0 answer=int(input()) n=answer for i in range(n): s=s+a a=a+1 print(s)
- 1
Information
- ID
- 597
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By