1 solutions

  • 0
    @ 2024-12-10 23:27:11

    C++ :

    #include<cstdio>
    #include<cstring>
    using namespace std;
    int main()
    {
        int a[400],n,i,j,len;
        while(scanf("%d",&n)!=EOF)
        {
            memset(a,0,sizeof(a));
            a[1]=1;len=1;
            for(i=1;i<=n;i++)
            {
             for(j=1;j<=len;j++)a[j]*=2;
             for(j=1;j<=len;j++)if(a[j]>9){a[j+1]+=(a[j]/10); a[j]%=10; }
             if(a[len+1]!=0)len++;
            }
            for(i=len;i>=1;i--)printf("%d",a[i]);
            printf("\n");
        }
        return 0;
    }
    
    
    • 1

    高精度入门第3题:高精度乘单精度《计算2的N次方》

    Information

    ID
    602
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
    0
    Accepted
    0
    Uploaded By