1 solutions
-
0
C :
#include<stdio.h> int main() { int n; while(scanf("%d",&n)!=EOF) printf("%d\n",n*n-n+2); return 0; }
C++ :
#include<iostream> using namespace std; const int N(1001); int f[N]; void init() { f[1]=2; for (int i=2;i<N;i++) f[i]=f[i-1]+2*(i-1); } int main() { init(); int n; while (cin>>n) cout<<f[n]<<endl; return 0; }
- 1
Information
- ID
- 641
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By