1 solutions

  • 0
    @ 2024-12-10 23:55:33

    C :

    #include<stdio.h>
    int main()
    {
    int n;
    while(scanf("%d",&n)!=EOF)
    printf("%d\n",n*n-n+2);
    return 0;
    }
    

    C++ :

    #include<iostream>
    using namespace std;
    const int N(1001);
    int f[N];
    void init()
    {
        f[1]=2;
        for (int i=2;i<N;i++)
            f[i]=f[i-1]+2*(i-1);
    }
    int main()
    {
        init();
        int n;
        while (cin>>n) cout<<f[n]<<endl;
        return 0;
    }
    
    • 1

    Information

    ID
    641
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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