1 solutions
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0
C++ :
#include<iostream> #include<cstdlib> #include<cmath> using namespace std; long long const b=10002; long long a[b]; int main() { int k,m,n; cin>>k; a[0]=0; a[1]=1; a[2]=1; for(int i=2;i<=b;++i) { int s=2; s++; a[i]=a[i-1]+a[i-2]; if(a[i]>k) { m=a[i-2]; n=a[i-1]; break; } } cout<<"m="<<m<<endl; cout<<"n="<<n; //system("pause"); return 0; }
Pascal :
var k,i,j:longint;a:array[0..100000]of longint; begin readln(k); a[0]:=1;a[1]:=1;i:=1; repeat i:=i+1; a[i]:=a[i-1]+a[i-2]; until a[i]+a[i-1]>k; writeln('m=',a[i-1]); writeln('n=',a[i]); end.
- 1
Information
- ID
- 653
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By