1 solutions

  • 0
    @ 2024-12-11 0:25:36

    C :

    #include<stdio.h>
    int n,x;
    int main()
    {scanf("%d",&n);
    	while(n--){
    		int t=0;scanf("%d",&x);
    		while(x>0){x=x>>1;t++;}
    		printf("%d\n",t);
    	}return 0;
    }
    
    

    C++ :

    #include<iostream>
    #include<cstdio>
    #include<cstring>
    #include<cmath>
    using namespace std;
    int main()                                                   
    {
        int n;
        cin>>n;
        int t,cc[n+1],pp=1,ll=0;
    	long long k,hh,s;
        for(int i=1;i<=n;i++)
        {
        	cin>>t;
        	k=1;
        	s=0;
        	hh=1;
        	for(int l=1;l>0;l++)
        	{
        		ll=l;
        		s+=k;
        		k*=2;
        		if(s>=t) break;
        	}
        	cc[pp]=ll;
        	pp++;
        }
        for(int i=1;i<=n;i++)
        {
        	cout<<cc[i]<<endl;
        }
    	return 0;
    }
    

    Java :

    import java.util.Scanner;
    
    public class Main {
    
    	public static void main(String[] args) {
    		// TODO Auto-generated method stub
    		Scanner sc = new Scanner(System.in);
    		int T = sc.nextInt();
    		while(T>0) {
    			int n = sc.nextInt();
    			for (int j = 0; j <= n; j++) {
    				if(n>=Math.pow(2, j-1)&&n<Math.pow(2, j)) {
    					System.out.println(j);
    					break;
    				}
    			}
    			T--;
    		}
    	}
    }
    
    
    • 1

    Information

    ID
    695
    Time
    1000ms
    Memory
    64MiB
    Difficulty
    (None)
    Tags
    # Submissions
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